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Evaluate: int(-pi)^pi(1-x^2)sinxcos^2xdx...

Evaluate: `int_(-pi)^pi(1-x^2)sinxcos^2xdx`

Text Solution

Verified by Experts

The correct Answer is:
`0`
Value `=0` since `(1-x^(2)) sinx cos^(2)x` is an odd function of `x`.
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