Evaluate: `int_(-pi//2)^(pi//2)(cosx)/(1+e^x)dx`

Answer

A

Explanation

`I=int_(-(pi)/2)^((pi)/2)(x^(2)cosx)/(1+e^(x))dx`………………1
`=int_(-(pi)/2)^((pi)/2)(x^(2)cosx)/(1+1/(e^(x))`(Replacing x by `-x`)
`:. I=int_(-(pi)/2)^((pi)/2)(x^(2)cosx.e^(x))/(1+e^(x))dx`……………..2
Adding 1 and 2 we get
`2I=int_(-(pi)/2)^((pi)/2)x^(2)cosx dx`
`:. I=int_(0)^((pi)/2)x^(2)cosxdx`
`=x^(2). sin x|_(0)^(pi//2)-int_(0)^((pi)/2)2x sin xdx`
`=(pi^(2))/4-2[(-xcosx)_(0)^(pi//2)-int_(0)^(pi//2)( -cosx)dx]`
`=(pi^(2))/4-2[1]=(pi^(2))/4-2`