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Let S be the area of the region enclosed...

Let `S` be the area of the region enclosed by `y=e^-x^2,y=0,x=0,a n dx=1.` Then `Sgeq1/e` (b) `Sgeq1=1/e` `Slt=1/4(1+1/(sqrt(e)))` (d) `Slt=1/(sqrt(2))+1/(sqrt(e))(1-1/(sqrt(2)))`

A

`Sge1/e`

B

`Sge1-1/e`

C

`Sle1/4(1+1/(sqrt(e)))`

D

`Sle1/(sqrt(2))+1/(sqrt(e))(1-1/(sqrt(2)))`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D

`Sgt1/e` (As area of retangle `OCDS=1//e`)

Since `e^(-x^(2))ge e^(-x)AAx epsilon[0,1]`, we have
`S gt int_(0)^(1)e^(-x) dx=(1-1/e)`
Area of rectange `OAPQ+` Area of rectangle `QBRSgtS`
or `Slt 1/(sqrt(2))(1)+(1-1/(sqrt(2)))(1/(sqrt(e)))`
Since `1/4(1+1/(sqrt(e)))lt1-1/e`
Option 3 is incorrect.
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