If `alpha=int_0^1(e^9x+3tan^((-1)x))((12+9x^2)/(1+x^2))dxw h e r etan^(-1)` takes only principal values, then the value of `((log)_e|1+alpha|-(3pi)/4)i s`

Answer

9

Explanation

`alpha=int_(0)^(1)e^(9x+3tan^(-1)x)((12+9x^(2))/(1+x^(2)))dx`
Let `9x+3tan^(-1)x=t`
`implies (9-3)/(1+x^(2))dx=dt`
`implies((12+9x^(2))/(1+x^(2)))dx=dt`
`impliesalpha=int_(0)^(9+(3pi)/4)e^(t)dt=e^(9+(3pi)/4)-1`
`implies log_(e)(1+alpha)=9=(3pi)/4`