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A box B(1) contains 1 white ball, 3 red ...

A box `B_(1)` contains 1 white ball, 3 red balls, and 2 black balls. An- other box `B_(2)` contains 2 white balls, 3 red balls. A third box `B_(3)` contains 3 white balls, 4 red balls, and 5 black balls.
If 1 ball is drawn from each of the boxes `B_(1),B_(2) and B_(3),` the probability that all 3 drawn balls are of the same color is

A

`82//648`

B

`90//648`

C

`558//648`

D

`566//648`

Text Solution

Verified by Experts

The correct Answer is:
A
P (required)
= P (all are white) + P (all are red) + P (all are black)
`=1/6xx2/9xx3/12+3/6xx3/9xx4/12+2/6xx4/9xx2/12=6/648+36/648+40/648=82/648`
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