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If x=e^y+e^((y+ tooo)) , where x >0,t h ...

If `x=e^y+e^((y+ tooo))` , where `x >0,t h e nfin d(dy)/(dx)`

Text Solution

Verified by Experts

The correct Answer is:
`(1-x)/(x)`
`"Here, "x=e^(y+x)`
`"or "log x= (y+x)`
`"or "y=log x-x`
`therefore" "(dy)/(dx)=(1)/(x)-1=(1-x)/(x)`
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