Home
Class 12
MATHS
If x=acos^3theta,y=bsin^3theta, f i n d ...

If `x=acos^3theta,y=bsin^3theta, f i n d (d^3y)/(dx^3)` at `theta=0.`

Text Solution

Verified by Experts

The correct Answer is:
Does not exist

`x=acos^(3) theta, y = b sin^(3)theta`
`y_(1)=(dy)/(dx)=(3b sin^(2) theta cos theta)/(-3a cos^(2) theta sin theta)`
`=-(b)/(a) tan theta, if sin theta ne 0, cos theta ne 0`
Therefore, `y_(1)` does not exist a `theta = 0.`
Hence, `y_(2) and y_(3)` do not exist at `theta=0.`
Promotional Banner

Topper's Solved these Questions

  • DIFFERENTIATION

    CENGAGE|Exercise Exercise 3.9|14 Videos
  • DIFFERENTIATION

    CENGAGE|Exercise Exercise (Single)|137 Videos
  • DIFFERENTIATION

    CENGAGE|Exercise Exercise 3.7|6 Videos
  • DIFFERENTIAL EQUATIONS

    CENGAGE|Exercise Question Bank|7 Videos
  • DOT PRODUCT

    CENGAGE|Exercise DPP 2.1|15 Videos

Similar Questions

Explore conceptually related problems

If x = a cos^(3)(Theta), y = a sin^(3)(Theta) find (d^(2)y)/(dx^(2)) .

Find (dy)/(dx) if x=3 cos theta- 2cos^(3)theta,y=3 sin theta -2sin^(3) theta.

If x=asec^(3)theta " and " y=atan^(3)theta " find " (dy)/(dx) " at " theta=pi/3 .

If x = a sin^(3)(Theta) y=a cos^(3)(Theta) find dy/dx .

If x = aCos^3 θ and y= aSin^3 θ then dy/dx=

The tangent at any point on the curve x=acos^3theta,y=asin^3theta meets the axes in Pa n dQ . Prove that the locus of the midpoint of P Q is a circle.

Show that the equation of the normal to the curve x=a cos ^(3) theta, y=a sin ^(3) theta at 'theta ' is x cos theta -y sin theta =a cos 2 theta .

Find the slope of the normal to the curve x=a cos^(3) theta,y=a sin^(3) theta at theta=(pi)/(4) .