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If `` represents the area of acute angled triangle ABC, then `sqrt(a^2b^2-4^2)+sqrt(b^2c^2-4^2)+sqrt(c^2a^2-4^2)=` `a^2+b^2+c^2` `(a^2+b^2+c^2)/2` `a bcosC+b ccosA+c acosB` `a bsinC+b csinA+c asinB`

A

`a^(2)+ b^(2) + c^(2)`

B

`(a^(2) + b^(2) + c^(2))/(2)`

C

`ab cos C + bc cos A + ca cos B`

D

`ab sin C + bc sin A + ca sin B`

Text Solution

Verified by Experts

The correct Answer is:
B, C

`2Delta = ab sin C rArr a^(2)b^(2) - 4Delta^(2) = a^(2) b^(2) cos^(2)C`
`rArr sqrt(a^(2) b^(2) - 4Delta^(2)) + sqrt(b^(2) c^(2) -4Delta^(2)) + sqrt(c^(2) a^(2) - 4 Delta^(2))`
`= ab cos C + bc cos A + ca cos B`
`= (a^(2) + b^(2) + c^(2))/(2)` (using cosine rule)
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