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BC is the base of the DeltaABC is fixed ...

BC is the base of the `DeltaABC` is fixed and the vertex A moves, satisfying the condition `cot.(B)/(2) + cot.(C)/(2) = 2 cot.(A)/(2)`, then

A

`b + c = a`

B

`b + c = 2a`

C

vertex A moves along a straight line

D

vertex A moves along an ellipse

Text Solution

Verified by Experts

The correct Answer is:
B, D
Given `(s(s-b))/(Delta) + ((s-c))/(Delta) = (2s(s-a))/(Delta)`
`rArr s-b + s - c = 2 (s-a)`
`rArr b+c = 2a`
So, locus of vertex A is an ellipse
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