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Two parallel chords of a circle of radiu...

Two parallel chords of a circle of radius 2 are at a distance. `sqrt(3+1)` apart. If the chord subtend angles `pi/k` and `(2pi)/k` at the center, where `k >0,` then the value of [k] is

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The correct Answer is:
3

`2 "cos"(pi)/(2k) + 2 "cos"(pi)/(k) = sqrt3 + 1`
or `"cos"(pi)/(2k) + "cos"(pi)/(k) = (sqrt3 +1)/(2)`
Let `(pi)/(k) = theta`. Then,
`cos theta + "cos"(theta)/(2) = (sqrt3 +1)/(2)`
or `2t^(2) + t - (sqrt3 + 3)/(2) = 0` [where `cos (theta//2) = t`]
or `t = (-1 +- sqrt(1 + 4 (3 + sqrt3)))/(4)`
or `= (-1 +- (2 sqrt3 + 1))/(4) = (-2 -2 sqrt3)/(4), (sqrt3)/(2)`
`rArr t = "cos"(theta)/(2) in [-1, 1] :. "cos"(theta)/(2) = (sqrt3)/(2)`
`rArr (theta)/(2) = (pi)/(6) rArr k = 3`
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