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If sinx+cos e cx=2, then sin^n x+cos e c...

If `sinx+cos e cx=2,` then `sin^n x+cos e c^n x` is equal to `2` (b) `2^n` (c) `2^(n-1)` (d) `2^(n-2)`

A

2

B

`2^n`

C

`2^(n-1)`

D

`2^(n-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`sinx+cosecx=2`
`or (sinx-1)^2=0`
`or sinx=1`
`rArr sin^nx+cosec^nx=1+1=2`
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CENGAGE-TRIGONOMETRIC FUNCTIONS -Exercise (Single)
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