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about to only mathematics

A

`sectheta(sectheta-tantheta)`

B

`(cos^2theta)/(1+sintheta)`

C

`1/(1+sintheta)`

D

`(1-sintheta)/cos^2theta`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
Using property of angle bisector, we get
`(OB)/(AB)=(OC)/(AC)rArr sectheta/tantheta=x/(1-x)`
`or x=sectheta/(sectheta+tantheta)`
`xsectheta(sectheta-tantheta)=1/(1+sintheta)`
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