Home
Class 12
MATHS
If 2sec^2 alpha- sec^4 alpha-2 cosec^2 a...

If `2sec^2 alpha- sec^4 alpha-2 cosec^2 alpha+cosec^4 alpha=15/4` then `tan alpha=`

A

`1//sqrt2`

B

`1//2`

C

`1//22sqrt2`

D

`-1//sqrt2`

Text Solution

Verified by Experts

The correct Answer is:
A, D

`2sec^2alpha-sec^4alpha-2cosec^2alpha+cosec^4alpha=15/4`
`or 2(sec^2alpha-cosec^2alpha)+(cosec^2alpha+sec^2alpha)xx(cosec^2alpha-sec^2alpha-sec^2alpha)=15/4`
`or (cosec^2alpha-sec^2alpha)[cosec^2alpha+sec^2alpha-2]=15/4`
`or 4(cot^2alpha-tan^2alpha)[cosec^2alpha+sec^2alpha)=15`
`or4(cot^4alpha-tan^4alpha)=15`
`or 4(1-tan^8alpha)=15tan^4alpha`
`or 4tan^8alpha+15tan^4alpha`
`or 4tan^8alpha+154tan^4alpha-4=0`
`or (4tan^4alpha-1)(tan^4alpha+4)=0`
`or tan^4alpha=1/4ot tan^4alpha=-4`
`or tan^2alpha=pm1/2`
`or tan^2alpha=+1/2`
`or tanalpha=pm1/sqrt2`
Promotional Banner

Topper's Solved these Questions

  • TRIGONOMETRIC FUNCTIONS

    CENGAGE|Exercise Exercise (Comprehension)|11 Videos
  • TRIGONOMETRIC FUNCTIONS

    CENGAGE|Exercise Exercise (Matrix)|3 Videos
  • TRIGONOMETRIC FUNCTIONS

    CENGAGE|Exercise Exercise (Single)|57 Videos
  • TRIGONOMETRIC EQUATIONS

    CENGAGE|Exercise Archives (Matrix Match Type)|1 Videos
  • TRIGONOMETRIC RATIOS AND TRANSFORMATION FORMULAS

    CENGAGE|Exercise Matrix Match Type|1 Videos

Similar Questions

Explore conceptually related problems

Prove that sin^2alpha-sin^4alpha= cos^2alpha-cos^4alpha

IF tan alpha = ( sin alpha - cos alpha )/( sin alpha + cos alpha) , then sin alpha + cos alpha is

For alpha=pi/7 which of the following hold(s) good? (a) tanalphatan2alphatan3alpha=tan3alpha-tan2alpha-tanalpha (b) cos e calpha=cos e c2alpha+cos e c4alpha (c) cosalpha-cos2alpha+cos3alpha=1/2 (d) 8cosalphacos2alphacos4alpha=1

if cos alpha + sin alpha = 3/4 , then sin ^6 alpha + cos ^6 alpha =

Prove that [1+cot alpha-sec(alpha+pi/2)] [1+cot alpha+sec (alpha+pi/2)]=2 cot alpha .

sin 3 alpha = 4 sin alpha sin(x + alpha) sin(x-alpha)

If sec alpha is the average of sec(alpha - 2beta) and sec(alpha + 2beta) then the value of (2 sin^2 beta - sin^2 alpha ) where beta!= n pi is

If n=1,2,3,……. then cos alpha cos 2 alpha cos 4 alpha ……. Cos 2^(n-1) alpha is equal to

Evaluate cos alpha cos 2 alpha cos 3 alpha..........cos 999alpha , where alpha=(2pi)/(1999)