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Three circles each of radius 1, touch on...

Three circles each of radius 1, touch one another externally and they lie between two parallel lines. The minimum possible distance between the lines is

A

`2+sqrt(3)`

B

`3+sqrt(3)`

C

4

D

`2+(1)/(sqrt(3))`

Text Solution

Verified by Experts

The correct Answer is:
A

`sin 60^(@)=(AD)/(2)`
`therefore AD=2 sin 60^(@)=(2sqrt(3))/(2)`
`therefore d=1+AD+1=2+sqrt(3)`
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