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A particle of mass m is projected with v...

A particle of mass m is projected with velocity making an angle of `45^(@)` with the horizontal When the particle lands on the level ground the magnitude of the change in its momentum will be .

A

`sqrt 2 "mv"`

B

Zero

C

2 mv

D

`("mv")/(sqrt 2)`

Text Solution

Verified by Experts

The correct Answer is:
A

The horizontal momentum does not change. The chois in vertical momentum is
`mv sin theta -(-mv sin theta)=2mv(1)/sqrt(2)=sqrt2 mv`
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