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A car is travelling with liner velcoity...

A car is travelling with liner velcoity v on a circular road of radius R. If its speed is increasing at the rate of a `ms^(-1)` , then the net acceleration will be.

A

`(v^(2))/(R)+a`

B

`(v^(2))/(R)-a`

C

`sqrt((v^(2)/R)^(2)+a^(2))`

D

`sqrt((v^(2)/R)^(2)-a^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
Tangential acceleration = `a_(r)=a`
radial acceleration = `a_(r)=(v^(2))/(R)`
net acceteration = `= sqrt(a_(r)^(2)+a_(r)^(2))=sqrt(a^(2)+(v^(2)/(R))^(2))`
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