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An object of mass 4 kg is being rotated ...

An object of mass 4 kg is being rotated with 120 rev. Per
minute in a horizontal circular path of radius 4m. Its kinetic energy is :

A

5120 J

B

4126 J

C

6000 J

D

346 J

Text Solution

Verified by Experts

The correct Answer is:
A
`"K.E"=(1)/(2)"mv"^(2)=(1)/(2)m xx(2 pi vR)^(2)`
`=(1)/(2)m xx 4 xx pi^(2) xx v^(2) xx R^(2)`
`"K.E"=m xx 2 xx pi ^(2) xx v^(2) xxR^(2)` `(3.14)^(2)`=9.85=10
`= 4 xx 2 xx 10 xx(120)/(60) xx(120)/(60) xx 4 xx 4`
`"K.E"=4 xx 2 xx 10 xx 2 xx 2 xx 16=5120 J`
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