Home
Class 12
PHYSICS
An alternating e.m.f. given by e=200 sin...

An alternating e.m.f. given by e=200 sin 50 t is applied to a circuit containing only a resistance of `50 Omega`. What is the value of r.m.s. current in the circuit?

A

`0.01`

B

`0.2`

C

`0.05`

D

`0.6`

Text Solution

Verified by Experts

Power factor `phi = (R)/(Z)`
`Z = sqrt (R ^(2) + X _(L) ^(2)) = sqrt (R ^(2) + (omega L ) ^(2))`
`Z = sqrt((30) ^(7) + ( 100 xx 400 xx 10 ^(-3)) ) = sqrt (900 + 160) = sqrt ( 2500)`
`Z = 50 Omega`
`therefore cos phi = ( R)/(Z) =(30)/(50) = 0.6`
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    PHYSICS WALLAH|Exercise LEVEL - 2|30 Videos

  • ALTERNATING CURRENT

    PHYSICS WALLAH|Exercise NEET PAST 5 YEARS QUESTIONS |8 Videos

  • CURRENT ELECTRICITY

    PHYSICS WALLAH|Exercise NEET Past 5 Years Questions|23 Videos

Similar Questions

Explore conceptually related problems

An alternating emf of 200 V, 50 Hz is applied a circuit containing a resistance of 100 Omega and inductance of 0.1 H in series. The powerr dissipated in the circuit is

Alternating e.m.f. of E = 220 sin 100 pi t is applied to a circuit containing an inductance of (1//pi) henry. Write equation for instantaneous current through the circuit. What will be the reading of a.c. galvanometer connected in the circuit ?

An e.m.f. E=4cos(1000t) volt is applied to an LR circuit of inductance 3mH and resistance 4ohm . The amplitude of current in the circuit is

An alternating emf, e=200 sin omegat is applied to a lamp, whose filament has a resistance of 1000Omega . The rms valve of current is

A sinusoidal voltage of amplitude 5V is applied to resistance of 500 Omega . The r.m.s. current in the circuit is

An a.c. Voltage given by e=100 sin(3.14 t + 60^(@)) is applied to a machine having a power rating of 500 W. The r.m.s. value of the current is the circuit is

An alternating e.m.f. E=10sqrt(2) sin omega volt is applied to a circuit containing a pure inductance L and a resistance and voltage acros the resistance is 6 v between the current and potential difference in this circuit is

An alternating emf, e=300 sin100 pit volt, is applied to a pure resistance of 100 Omega . The rms current through the circuit is

In an ac circuit , an alternating voltage e = 200 sqrt2 sin 100 t volts is connected to a capacitor of capacitance 1 mu F . The rms value of the current in the circuit is :

Alternating voltage V = 400 sin ( 500 pi t ) is applied across a resistance of 0.2 kOmega . The r.m.s. value of current will be equal to