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Electromagnetic radiation of frequency n...

Electromagnetic radiation of frequency `n`, wavelength `lambda`, travelling with velocity v in air, enters a glass slab of refractive index `mu`. The frequency, wavelength and velocity of light in the glass slab will be respectively

A

`n, 2 lambda` and `(v)/(mu)`

B

`(2n)/(mu), (lambda)/(mu)` and v

C

`(n)/(mu), (lambda)/(mu)` and `(v)/(mu)`

D

`n, (lambda)/(mu)` and `(v)/(mu)`

Text Solution

Verified by Experts

The correct Answer is:
D

Frequency = n, Wavelength `= lambda`, Velocity of air = v and refractive index of glass slab `= mu`.
Frequency remains the same, when light changes the medium. Refractive index is the ratio of wavelengths in vacuum and in the givn medium. Similarly refractive index is also the ratio of velocities in vacuum and in the given medium.
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