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A light of wavelength 5890Å falls normal...

A light of wavelength `5890Å` falls normally on a thin air film. The minimum thickness of the film such that the film appears dark in reflected light is

A

`2.945 xx 10^(-7)m`

B

`3.945 xx 10^(-7)m`

C

`4.95 xx 10^(-7)m`

D

`1.945 xx 10^(-7)m`

Text Solution

Verified by Experts

The correct Answer is:
A

If thin film appears dark
`2 mu t cs r = n lambda` [for normal incidence `r = 0^(@)`]
`2 mu t = n lambda rArr t = (n lambda)/(2 mu)`
`t_("min") = (5890 xx 10^(-10))/(2 xx 1) = 2.945 xx 10^(-7)m`
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