For a parallel beam of monochromatic light of wavelength `'lambda'` diffraction is produced by a single slit whose width `'a'` is of the order of the wavelength of the light. If `'D'` is the distance of the screen from the slit, the width of the central maxima will be

Options

A. `(D lambda)/(a)`
B. `D a//lambda`
C. `12D//a`
D. `(2 D lambda)/(a)`

Answer

D

Explanation

Linear width of central maxima `= 2 D theta = 2D(lambda)/(a)`