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In Young's double slit experiment, the s...

In Young's double slit experiment, the sepcaration between the slits is halved and the distance between the slits and the screen is doubled. The fringe width is

A

w

B

9w

C

4w

D

2w

Text Solution

Verified by Experts

The correct Answer is:
C
In interference
Fringe width `= (lambda D)/(d) = w` (given
`w. = (lambda xx 2D)/((d)/(2)) = 4 xx (lambda D)/(d) = 4 w`
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