Home
Class 12
PHYSICS
Two coherent sources of intensity ratio ...

Two coherent sources of intensity ratio `alpha ` interface . In interference pattern `(I_("max") - I_("min"))/(I_("max") + I_("min")) = `

A

`2sqrt((alpha)/(1+alpha))`

B

`(2sqrt(alpha))/(1+alpha)`

C

`(1+alpha)/(2sqrt(alpha))`

D

`(1-alpha)/(1+alpha)`

Text Solution

Verified by Experts

The correct Answer is:
B
Given `(I_(1))/(I_(2)) = alpha`
`I_("max") = (sqrt(I_(1)) + sqrt(I_(2)))^(2) = I_(1) + I_(2) + 2sqrt(I_(1)I_(2))`
`I_("min") = sqrt(I_(1)) - sqrt(I_(2)))^(2) = I_(1) + I_(2) - 2sqrt(I_(1)I_(2))`
`I_("max")+ I_("min") =2[I_(1) + I_(2)] rArr 2[alpha I_(2) + I_(2)] = 2I_(2) [I + alpha]`
`I_("max") - I_("min") = 4sqrt(I_(1)I_(2)) = 4sqrt(alpha I_(1)I_(2)) = 4I_(2) sqrt(alpha)`
`(I_("max") - I_("min"))/(I_("max") + I_("min")) = (4I_(2)sqrt(alpha))/(2I_(2)[1+alpha]) = (2sqrt(alpha))/(1+alpha)`
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    PHYSICS WALLAH|Exercise Level -2|30 Videos

  • UNITS AND MEASUREMENTS

    PHYSICS WALLAH|Exercise NEET PAST 5 YEARS QUESTIONS |10 Videos

  • WAVES

    PHYSICS WALLAH|Exercise NEET PAST 4 YEARS QUESTIONS |15 Videos

Similar Questions

Explore conceptually related problems

Two coherent sources of intensity ratio alpha interfere. In interference pattern (I_(max)-I_("min"))/(I_(max)-I_("min")) =

Two doherent sources of intensity ratio alpha interfere in interference pattern (I_(max)-I_(min))/(I_(max)+I_(min)) is equal to

Two coherent sources of light of intensity ratio beta interfere. Prove that the interference pattern, (I_(max)-I_(min))/(I_(max)+I_(min))=(2sqrtbeta)/(1+beta) .

The interference pattern is obtained with two coherent light sources of intensity ratio n. In the interference patten, the ratio (I_(max)-I_(min))/(I_(max)+I_(min)) will be

Two coherent sources of intensity ratio beta^2 interfere. Then, the value of (I_(max)- I_(min))//(I_(max)+I_(min)) is

Two coherent light sources having intensity in the ratio 2x produce an interference pattern. The ratio (I_(max)-I_(min))/(I_(max)+I_(min)) will be :

Two coherent sources with intensity ratio alpha interfere. Then, the ratio (l_(max)-l_("min"))/(l_(max)+l_("min")) is

Two coherent sources of light of intensity ratio beta produce interference pattern. Prove that in the interferencepattern (I_(max) - I_(min))/(I_(max) + (I_(min))) = (2 sqrt beta)/(1 + beta) where I_(max) and I_(min) are maximum and mininum intensities in the resultant wave.