A strip of nickel metal is dipped in a 1 molar solution of `Ni (NO_(3))_(2)` and a strip of silver metal is dipped in a 1 molar solution of `AgNO_(3)`. An electrochemical cell is created when the two solutions are joined by salt bridge and two strips are joined by wire to a voltmeter.
Answer the following questions.
Calculate the cell potential `(E_("cell"))` at `25^(@)C` for the cell if the initial concentration of `Ni (NO_(3))_(2)`, is 0.100 molar and the initial concentration of `AgNO_(3)` is 1.00 molar.
`[E_(Ni^(2+)//Ni)= -0.25V, E_("Ag^(+)//Ag)=0.80V, log 10^(-1)= -1]`

Explanation

Given, `[Ni^(2+)]=0.100M`
`[Ag^(+)]=1.00M`
`E_("cell") =E_("cell")^(@) =(0.0591)/(n)"log"([Ni^(2+)])/([Ag^(+)]^(2))`
`=1.05 - (0.0591)/(2) "log"((0.1))/((1.0)^(2))`
`=1.05 -0.0295 (-1) =1.05 +0.0295`
`E_("cell")=1.08V`