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The relation between time t and displace...

The relation between time t and displacement x is `t = alpha x^2 + beta x,` where `alpha and beta` are constants. The retardation is

A

`-2alphav^(3)`

B

`2betav^(2)`

C

`2alphabetav^(2)`

D

`abeta^(2)v^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`t=alphax^(2)+betaxrArr1 =(2alpha x+beta)vrArr v=1/(beta+2alphax)`
`:.` Acceleration `=(2alpha)/((beta+2alphax)^(2))v=2alphav^(3)`
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