If the radii of circular path of two particles are in the ratio of `4:3`, then in order to have same centripatal acceleration, their speeds should be in the ratio of :

Answer

D

Explanation

`x=40+12t-t^(3)`
Speed `(dx)/(dt)=0+12-3t^(2)rArr t= +- 2`sec
`:. x(2)=40+12xx2-2^(3)`
`=64-8=56 m`
at `t=0, x(0)=40`
`Deltax=x(2)-x(0)=16`