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A point moves along an arc of a circle o...

A point moves along an arc of a circle of radius R. Its velocity depends on the distance covered s as `v=asqrts`, where a is a constant. Find the angle `alpha` between the vector of the total acceleration and the vector of velocity as a function of s.

A

`tan alpha=R/(2s)`

B

`tan alpha=(2a)/R`

C

`tan alpha=(2R)/s`

D

`tan alpha=s/(2R)`

Text Solution

Verified by Experts

The correct Answer is:
B
`tan alpha=v^(2)/Rxx1/(dv//dt)=(a^(2)s)/(Rav//2sqrt(s))=(2s)/R`
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