A body of mass `m` attached to a spring which is oscillating with time period `4` seconds. If the mass of the body is increased by `4 kg`, Its timer period increases by `2 sec`. Determine value of initial mass `m`.
Text Solution
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In `I^(st)` case : `T = 2pisqrt((m)/(k)) rArr 4 = 2pisqrt((m)/(k))`….(i) and in `II^(nd)` case: `6 = 2pi sqrt((m+4)/(k))`…..(ii) Divide `(i)` by `(ii) (4)/(6) = sqrt((m)/(m+4)) rArr (16)/(36) = (m)/(m+4) rArr m = 3.2 kg`
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