A simple pendulum is suspended from the ceilling of a left. When the lift is at rest, its time period is `T`. With what accleration should lift be acclerated upwards in order to reduce its time period to `(T)/(2)`.
Text Solution
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In stationary lift `T = 2pisqrt((l)/(g))"……(i)` , in accelerated lift `(T)/(2) = T' = 2pisqrt((l)/(g+a))"……."(ii)` Divide (i) by (ii) `2 = sqrt((g+a)/(g)) rArr g + a = 4 rArr a = 3g`
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