Values of the acceleration `A` of a particle moving in simple harmonic motion as a function of its displacement `x` are given in the table below. `|{:(A(mm s^(-2)),16,8,0,-8,-16),(x(mm),-4,-2,0,2,4):}|` The pariod of the motion is
A
`1/(pi)s`
B
`(2)/(pi)s`
C
`(pi)/(2)s`
D
`pis`
Text Solution
Verified by Experts
The correct Answer is:
D
In SHM `a = -omega^(2)x`. So `16 = -omega^(2) (-4) rArr omega = 2 rArr "Time period" T = (2pi)/(omega) = (2pi)/(2) = pis`
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