The period of oscillation of a mass m suspended by an ideal spring is 2s. If an additional mass of 2 kg be suspended, the time period is increased by 1s. Find the value of m.
A
`2 kg`
B
`1 kg`
C
`1.6 kg`
D
`2.6 kg`
Text Solution
Verified by Experts
The correct Answer is:
C
Here `2pisqrt((m)/(k)) = 2s` and `2pisqrt((m+2)/(k)) = 3s rArr (3)/(2) = sqrt((m+2)/(3)) rArr = 9/4 = (m+2)/(m)` which yield `m = 1.6 kg`
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