The angle made by the string of a simple pendulum with the vertical depends on time as `theta=pi/90sin[(pis^-1)t]`. Find the length of the pendulum if `g=pi^2ms^-2`
While measuring the acceleration due to gravity by a simple pendulum , a student makes a positive error of 1% in the length of the pendulum and a negative error of 3% in the value of time period . His percentage error in the measurement of g by the relation g = 4 pi^(2) ( l // T^(2)) will be
Time period of a simple pendulum is 2s. If its length is increased by 4 times, then its period becomes……….
The angle made by the tangent with the + ve direction of X-axis to x=e^(t)cos t, y = e^(t)sin t at t=(pi)/(4) is ……….
For simple pendulum, T = 2pi sqrt((l)/(g)) where T is the periodic time and l is the length of pendulum. If there is 4% error in the measure of periodic time then find the error percentage in the length of pendulum.
Assertion : As the mass of simple pendulum increases, its periodic time increases. Reason : Periodic time of simple pendulum is T= 2pi sqrt((l)/(g)) .
The period of oscillation of a simple pendulum is given by T=2pi sqrt((l)/(g)) . The length l of the pendulum is about 0.5s. The time of 100 oscillations is measured with a watch of 1 s resolution. Calcualte percentage error in measurment of g.
The two legs of a right triangle are sin theta +sin ((3pi)/2-theta) and cos theta -cos( (3pi)/2-theta) The length of its hypotenuse is
The charge density of uniformly charged infinite plane is sigma . A simple pendulum is suspended vertically downward near it. Charge q_0 is placed on metallic bob. If the angle made by the string is theta with vertical direction then ______ .
Check the accuracy of the relation T=2pisqrt((L)/(g)) for a simple pendulum using dimensional analysis.
