The time period (T) of a spring mass system depends upon mass (m) & spring constant (k) & length of the spring (l)[k=("Force")/("length")] . Find the relation among T, m , l & k using dimensional method.
Is the temperature of an isolated system of gas be changed ?
Let T_(1)" and "T_(2) be the time periods of spring A and B when mass M is suspended from the end of the spring. If both springs are taken in series and the same mass M is suspended from the series combination, the time period is T, then
The period of oscillation of a mass m suspended by an ideal spring is 2s. If an additional mass of 2 kg be suspended, the time period is increased by 1s. Find the value of m.
Answer the following question : Time period of a particle in SHM depends on the force constant k and mass m of the particle: T=2pisqrt(m/k) . A simple pendulum executes SHM approximately. Why then is the time period of a pendulum independent of the mass of the pendulum?
The spring mass system oscillating horizontally. What will be the effect on the time period if the spring is made to oscillate vertically?
The time period of mass suspended from a spring is T. If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be…….
The time period of a simple pendulum in a stationary train is T. The time period of a mass attached to a spring is also T. The train accelerates at the rate 5 m//s^(2) . If the new time periods of the pendulum and spring be T_(P) and T_(S) respectively, then :-
Diameter and mass of a planet is double that earth. Then time period of a pendulum at surface of planet is how much times of time period at earth surface :-
In a horizontal spring - mass system mass m is released after being displaced towards right by some distance t = 0 on a friction-less surface. The phase angle of motion in radian when it is first time passing through equilibrium position is equal to
