For a simple harmonic motion with given angular frequency `omega`, two arbitrary initial conditions are necessary and sufficient to determine the motion completely. These initial conditions may be
A
(a)Amplitude and initial phase
B
(b)Amplitude and total energy of oscillation
C
(c)Initial phase and total energy of oscillation
D
(d)Initial position and initial velocity
Text Solution
Verified by Experts
The correct Answer is:
A,D
Spring constant in parallel combination `k' = 2k + 2k = 4k` `:. T = 2pisqrt((m)/(k')) = 2pisqrt((m)/(4k)) = 2pisqrt((m)/(k)) xx (1)/(sqrt(4)) = (T)/(sqrt(4)) = (T)/(2)`
Topper's Solved these Questions
SIMPLE HARMONIC MOTION
ALLEN |Exercise SOME WORKED OUT EXAMPLES|29 Videos
A particle executes simple harmonic motion with frequency f. The frequency of its potential and kinetic energy is………
A particle of mass m executes simple harmonic motion with amplitude a and frequency v. The average kinetic energy during its motion from the position of equilinrium to the end is.
Two simple harmonic motions of angular frequency 100 and 1000 rad s^(-1) have the same displacement amplitude. The ratio of their maximum acceleration is………
Plot the corresponding reference circle for each of the following simple harmonic motions. Indicate the initial (t =0) position of the particle, the radius of the circle, and the angular speed of the rotating particle. For simplicity, the sense of rotation may be fixed to be anticlockwise in every case: (x is in cm and t is in s).
For the given statements identify the necessary and sufficient conditions. t: If you drive over 80 km per hour, then you will get a fine.