An electron of mass `m` and charge `e` initially at rest gets accelerated by a constant electric field `E`. The rate of change of de-Broglie wavelength of this electron at time `t` ignoring relativistic effects is

Answer

`(-h)/(inEt^(2))`

Explanation

`lambda_("de-brogile")=(h)/sqrt(2mK)=h/(mv)`
`v=u+at=0+((e E)/m)timplies lambda=h/(e Et)`
`implies (d lambda)/(dt)=-(h)/(e Et^(2))`