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PEARSON IIT JEE FOUNDATION-EXPRESSIONS AND SPECIAL PRODUCTS -TEST YOUR CONCEPTS (VERY SHORT ANSWER TYPE QUESTIONS)
- Fill in the blanks. 5x^(2)(x-y) =
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- 4x^(2) - 4x + 1 = ("")^(2)
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- Fill in the blanks. (x+a)(x+b)=
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- Fill in the blanks. x^(2)- y^(2) =
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- Fill in the blanks. (a+ 3b)^(2)
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- If (x+1/x)=sqrt(7), then x^(2) + 1/x^(2) =
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- (a - 1) (a^(2) - 2a + 1) = ""
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- (a+b)(sqrt(a) + sqrt(b))(sqrt(a)- sqrt(b)) =
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- If a=3 and b=-2, then a^(2) + b^(2) + 2ab =
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- (x+a)(x-b) =
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- The degree of 4x^(2) is
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- The degree of -3x^(3) + 5x^(2) + 4 is "".
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- The degree of xyz is "".
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- The degree of x + y + z is "".
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- The zero of x + 2 is ""
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- The zero of x - 3 is ""
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- The zero of 3x + 2 is "".
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- The zero of 12x-3 is
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- The expanded form of (x + y) ( x - y) is a ""
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- Find the degree of (x^(2) - x)^(2).
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