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Two different electrolytic cells filled ...

Two different electrolytic cells filled with molten `Cu(NO_(3))_(2)` and molten `Al ( NO_(3))_(2)`, respectively are connected in series. When electricity is passed 2.7g Al is deposited on electrode. Calculate the weight of Cu deposited on cathode.
[ Cu = 63.5, Al = 27.0 g `"mol"^(-1)`]

A

190.5g

B

9.525g

C

63.5g

D

31.75g

Text Solution

Verified by Experts

The correct Answer is:
b
Accoring to Faraday.s second law,
`( w_(1))/( E_(1)) = ( w_(2))/( E_(2))` ( 1 for Al and 2 for Cu )
`( 2.7 xx 3) /( 27) = ( w_(2) xx 2)/( 63.5) ( E_(Al) = 27//3 ` and `E_(Cu ) = 63.5//2`)
`w_(2) = 9.525g`
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