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The Boolean expression ~(pvvq)vv(~p^^q) ...

The Boolean expression `~(pvvq)vv(~p^^q)` is equivalent to (1) `~p` (2) `p` (3) `q` (4) `~q`

A

`pwedge (~q)`

B

`p vee(~q)`

C

`(~p) wedge (~q)`

D

`p wedge q`

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Verified by Experts

The correct Answer is:
C
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