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Evaluate: lim(n->oo)ncos(pi/(4n))sin(pi/...

Evaluate: `lim_(n->oo)ncos(pi/(4n))sin(pi/(4n))`

Text Solution

Verified by Experts

The correct Answer is:
`pi//4`
`L=underset(ntooo)limncos((pi)/(4n))sin((pi)/(4n))`
`=underset(ntooo)lim(cos((pi)/(4n))sin((pi)/(4n)))/(((pi)/(4n))4/pi)`
`=cos(0)xx1xx(pi)/(4)=(pi)/(4)`
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