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y=f(x) satisfies the relation int(2)^(x)...

`y=f(x)` satisfies the relation `int_(2)^(x)f(t)dt=(x^(2))/2+int_(x)^(2)t^(2)f(t)dt`
The value of `int_(-2)^(2)f(x)dx` is

A

`0`

B

`-2`

C

`2log_(e)2`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`int_(2)^(x)f(t)dt=(x^(2))/2+int_(x)^(2)t^(2)f(t)dt`
Differentiating w.r.t `x` we get

`f(x)=x+(-x^(2)f(x))`
or `f(x)[1+x^(2)]=x`
Let `y=f(x)=x/(1+x^(2))`
or `yx^(2)-x+y=0`
Since `x` is real `Dge0`
or `1-4y^(2)ge0`
or `y epsilon [-1/2,1/2]`
Also `f(x)` is an odd funtion. Hence `int_(-2)^(2)f(x)dx=0`
`f'(x)=(1+x^(2)-2x^(2))/(1+x^(2))-(1-x^(2))/(1+x^(2))ge0`
or `x^(2)-1le0`
or `x epsilon[-1,1]`
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