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"If "y=(root(3)(1+3x)root(4)(1+4x)root(5...

`"If "y=(root(3)(1+3x)root(4)(1+4x)root(5)(1+5x))/(root(7)(1+7x)root(8)(1+8x)),` then y'(0) is equal to -

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`y=(root(3)(1+3x)root(4)(1+4x)root(5)(1+5x))/(root(7)(1+7x)root(8)(1+8x))`
`log_(e)y=(1)/(3)log_(e)(1+3x)+(1)/(4)log_(e)(1+4x)+(1)/(5)log_(e)(1+5x)-(1)/(7)log_(e)(1+7x)-(1)/(8)log_(e)(1+8x)`
Differentiating w.r.t. x
`(1)/(y)xx(dy)/(dx)=(1)/(1+3x)+(1)/(1+4x)+(1)/(1+5x)-(1)/(1+5x)-(1)/(1+7x)-(1)/(8x)`
`"At "x=0, y=1`
`rArr" "((dy)/(dx))_(x=0)=1+1+1-1-1=1`
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