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y = sin^(-1)(1/sqrt(1+x^2)) + cos^(-1)(1...

`y = sin^(-1)(1/sqrt(1+x^2)) + cos^(-1)(1/sqrt(1+x^2))`. find `dy/dx`.

Text Solution

Verified by Experts

From tringular conversions,
`y=sin^(-1)((x)/(sqrt(1+x^(2))))+cos^(-1)((1)/(sqrt(1+x^(2))))`
`=tan^(-1)x+tan^(-1)x=2 tan^(-)x`
`therefore" "(dy)/(dx)=(2)/(1+x^(2))`
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