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"Find "(dy)/(dx)" for "y=sin(2x^(2)+3x+1...

`"Find "(dy)/(dx)" for "y=sin(2x^(2)+3x+1).`

Text Solution

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`"Let "y= sin(x^(2)+1).`
Putting `u=x^(2)+1," we get y sin u"`
`therefore" "(dy)/(dx)=cos u and (du)/(dx) = 2x`
`"Now, "(du)/(dx)=(dy)/(du).(du)/(dx)`
`= (cos u) (2x)=2x cos(x^(2)+1)`
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