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If:x/a costheta+y/b sin theta=1 and x/a ...

`If:x/a costheta+y/b sin theta=1 and x/a sin theta-y/b cos theta=1,` Prove that : `(x^2)/(a^2)+(y^2)/(b^2)=2`

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Verified by Experts

The correct Answer is:
`x^2/a^2+y^2/b^2=2`
Squaring and adding, we have `x^2/a^2+y^2/b^2=2`
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