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If any quadrilateral ABCD, prove that `"sin"(A+B)+sin(C+D)=0` `"cos"(A+B)=cos(C+D)`

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In quadrilateral `ABCD, A+B+C+D=2pi`.
(a) `sin(A+B)+sin(C+D)=sin(A+B)+sin(2pi-(A+B))`
`=sin(A+B)-sin(A+B)=0`
(b) `cos(A+B)=cos(C+D)`
`=cos(2pi-(C+D))=cos(C+D)`
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CENGAGE PUBLICATION-TRIGONOMETRIC FUNCTIONS -Concept Application Exercises 2.14
  1. If any quadrilateral ABCD, prove that "sin"(A+B)+sin(C+D)=0 "cos"(A...

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