If tantheta =3," then " (sintheta-costhe...

If `tantheta =3," then " (sintheta-costheta)/(sintheta+costheta)` is equal to

A

0

B

1

C

`1/2`

D

2

Text Solution

Verified by Experts

The correct Answer is:

C

`5tantheta=4ortantheta=4/5`
Now, `(5sintheta-3costheta)/(5sintheta+2costheta)=(5(sintheta)/costheta-3)/(5sintheta/tantheta+2)`
`=(5tantheta-3)/(5tantheta+2)`
`=(5xx4/5-3)/(5xx4/5+2)=1/6`

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Knowledge Check

(1+sintheta-costheta)/(1+sintheta+costheta) =

A

`cot(theta/2)`

B

`sin(theta/2)`

C

`cos(theta/2)`

D

`tan(theta/2)`

If 4cottheta =3 then value of ((sintheta-costheta)/(sintheta+costheta))

A

2/7

B

5/7

C

1/7

D

1

int(cos2theta)/((sintheta+costheta)^2)d theta is equal to

A

`(-1)/(sintheta+costheta)+c`

B

`logabs(sintheta+costheta)+c`

C

`logabs(sintheta-costheta)+c`

D

`log(sintheta+costheta)^2+c`

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