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The equation of the image of the circle ...

The equation of the image of the circle `x^2+y^2+16x-24y+183=0` by the line mirror `4x+7y+13=0` is :

A

`x^(2) +y^(2) +32x - 4y +235 = 0`

B

`x^(2) +y^(2) +32x +4y - 235 = 0`

C

`x^(2) +y^(2) +32x - 4y - 235 = 0`

D

`x^(2) +y^(2) +32x +4y +235 = 0`

Text Solution

Verified by Experts

The correct Answer is:
D
The image of the centre of the given circle i.e., `(-8,12)` in the line `4x +7y +13 =0` is `(-16,-2)`.
Also, radius `= sqrt(64+144-183) =5`
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