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Let A (-4,0) ,B(4,0) Number of poin...

Let `A (-4,0) ,B(4,0) ` Number of points `c= (x,y)` on circle `x^2+y^2=16` such that area of triangle whose verties are A,B,C is positive integer is:

A

14

B

15

C

16

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B

`A = (1)/(2), 8.4. sin theta = |16 sin theta|`
Now, `sin theta` can be equal to `(1)/(16),(2)/(16),..(15)/(16)`
i.e., there are 15 points in each quadrant.
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