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If m(x-2)+sqrt(1-m^2) y= 3 , is tangent ...

If `m(x-2)+sqrt(1-m^2) y= 3` , is tangent to a circle for all `m in [-1, 1]` then the radius of the circle is (a) 1.5 (b) 2 (c) 4.5 (d) 3

A

1.5

B

2

C

4.5

D

3

Text Solution

Verified by Experts

The correct Answer is:
D
`(x-2) cos theta +y sin theta = 3` is tangent to the circle `(x-2)^(2) +y^(2) =3^(2)`.
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