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Let circle C1 : x^2 + (y-4)^2 = 12 inter...

Let circle `C_1 : x^2 + (y-4)^2 = 12` intersects circle `C_2: (x-3)^2 +y^2=13` at A and B. A quadrilateral ACBD is formed by tangents at A and B to both circles. The diameter of circumcircle of quadrilateral ACBD is

A

4

B

5

C

6

D

9.25

Text Solution

Verified by Experts

The correct Answer is:
B
Both circles cut each other orthogonally.
Thus, C and D will be centres of two circles also CD will be diameter of circumcircle of quadrilateral ABCD.
Diameter `= sqrt(3^(2)+4^(2)) =5`
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